Identify all the hazards and number of stalls in the assembly code. Assume there is no forwarding, no branch prediction, and no duplicate copies of instruction memory or data memory.
Loop:
LSL X9, X20, #3
ADD X9, X9, X22
LDUR X9, [X9, #0]
ADD X9, X9, X21
LSL X10, X19, #3
ADD X10, X10, X22
STUR X9, [X10, #0]
LSL X9, X21, #3
ADD X9, X9, X22
LDUR X9, [X9, #0]
SUB X19, X20, X9
CBNZ X19, Loop
ADDI X19, XZR, #32
Expert Answer