Solved: Problem 15-05 (Algorithmic) Consider the following time series data Week1 2 3 4 5 6

Problem 15-05 (Algorithmic) Consider the following time series data Week1 2 3 4 5 6 Value 16 12 14 13 15 14 a. Choose the correct time series plot. 20r Time Series Value 18 16 14 12 10 20r Time Series Value 18 16 12 10 Week(t) Week(t)Solved: Problem 15-05 (Algorithmic) Consider the following time series data Week1 2 3 4 5 6 1Solved: Problem 15-05 (Algorithmic) Consider the following time series data Week1 2 3 4 5 6 2
Problem 15-05 (Algorithmic) Consider the following time series data Week1 2 3 4 5 6 Value 16 12 14 13 15 14 a. Choose the correct time series plot. 20r Time Series Value 18 16 14 12 10 20r Time Series Value 18 16 12 10 Week(t) Week(t)

Expert Answer

a) Ans (i)

The graph correctly depicts the value against the week entries. There is zig-zag pattern

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b) The 3 week moving average is: (M1+M2+M3)/3

Example: Week 4 = (16+12+14)/3 = 14

Solved: Problem 15-05 (Algorithmic) Consider the following time series data Week1 2 3 4 5 6 3

Week Value (D) Forecast (F) Error (D-F) Error Abs Error Sq
1 16
2 12
3 14
4 13            14.00            (1.00)           1.00                     1
5 15            13.00             2.00           2.00                     4
6 14            14.00                  –               –                   –
           14.00

Week 7 forecast = 14

MSE = (1+4+0)/((3-1) = 2.5

c)

Solved: Problem 15-05 (Algorithmic) Consider the following time series data Week1 2 3 4 5 6 4

Week Value (D) Forecast (F) Error (D-F) Error Abs Error Sq
1 16
2 12            16.00
3 14            15.20
4 13            14.96            (1.96)           1.96               3.84
5 15            14.57             0.43           0.43               0.19
6 14            14.65            (0.65)           0.65               0.43
           14.52

Week 7 forecast = 14.52

MSE = (3.84+0.19+0.43)/(3-1) = 2.23

d) Exponential smoothing forecast is better due to lower MSE. Hence, less error

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