Expert Answer
Conditional profit table for jam is
Produce | Demand | ||||
5 cases | 6 cases | 7 cases | 8 cases | the expected monetary value (EMV) for each alternative | |
P=0.05 | P=0.20 | P=0.40 | P=0.35 | ||
5 cases | 200 | 200 | 200 | 200 | 200 |
6 cases | 150 | 240 | 240 | 240 | 235.5 |
7 cases | 100 | 190 | 280 | 280 | 253 |
8 cases | 50 | 140 | 230 | 320 | 234.5 |
Calculation if 5 cases produced:
(5/5 cases) = Revenue – cost = $90 *5 -$50 *5 = $200 (profit)
(5/6 cases) = $90 *5 -$50 *5 = $200
(5/7 cases) = $90 *5 -$50 *5 = $200
(5/8 cases) = $90 *5 -$50 *5 = $200
[Note: the maximum sale will be equal to production even if demand is higher)
The expected monetary value (EMV) for each alternative
= $200 * 0.05 + $200 * 0.20 + $200 *0.40 + $200 *0.35 = $200
Similarly we can calculate if 6, 7 and 8 cases are produced (lets calculate for 7 also)
(7/5 cases) = $90 *5 -$50 *7 = $100
(7/6 cases) = $90 *6 -$50 *7 = $190
(7/7 cases) = $90 *7 -$50 *7 = $280
(7/8 cases) = $90 *7 -$50 *7 = $280
Expected Value of number of cases demanded = 5 *0.05 + 6 * 0.20 + 7 * 0.40 + 8 * 0.35 = 7.05 cases or 7 cases (nearest whole number) of Jam should Susan manufacture each month
The number of cases that Susan produce to achieve maximum expected value (EMV) is 7 cases as it has maximum expected profit (refer the above table)
The EMV of stocking this number of cases is
= $100 * 0.05 + $190 * 0.20 + $280 *0.40 + $280 *0.35 = $253