Question & Answer: If L_1 and L_2 are languages, the difference of L_1 and L_2 is L_1 – L_2 = {x|x element l_1 and x notelement L_2}. a. Us…..

If L, and L2 are languages, the difference of L, and Lz is L-L2-lx e L, and x L) a. Using the product construction to combine two DFAs M = (Q, Σ, δ-%-Fi) and M, = (R, Σ, δ2, r, F2), what should the set of accepting states be so that the resulting machine accepts LM)- L(M)? b. Prove that the regular sets are closed for set difference, without using the product construction.

If L_1 and L_2 are languages, the difference of L_1 and L_2 is L_1 – L_2 = {x|x element l_1 and x notelement L_2}. a. Using the product construction to combine two DFAs M_1 = (Q, sigma, delta_1, q_0, F_1) and M_2 = (R, sigma, delta_2, r_0, F-2), what should the set of accepting states be so that the resulting machine accepts L(M_1)- L(M_2)? b. Prove that the regular sets are closed for set difference, without using the product construction.

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Question & Answer: If L_1 and L_2 are languages, the difference of L_1 and L_2 is L_1 - L_2 = {x|x element l_1 and x notelement L_2}. a. Us..... 1

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