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I urgently need CORRECT ANSWER. if you can’t solve please don’t answer this.
10) Consider the following C code snippet: int number = 1001, copy = 0, local; local number; while (local-0) copy = copy * 10; copy-copy + local % 10; local-local/10; if (numbercopy) printf (“Iam Succeed”) printf (“Iam lost” else is the code segment correct? If correct what is the output? a) lam lost b) lam Succeed c) Error d) None of the above ●d
Expert Answer
10)
Answer: b) Iam Succeed
Explanation: In the source code, the reverse of number is calculated. Firstly the number is saved for the number by 1001. which is then passed to the variable local. The reverse of the number is calculated only when local is not equal to 0. As the condition satisfies, the value of copy is multiplied by 10. After this, the result is saved in copy variable which is initialized by 0 previously. Now, the modulous is taken of local value which is added to the copy variable. Then local variable is divided by 10 and result is saved in local variable itself. This process is repeated until the local value becomes 0.
Then if the value of number is eqivalent to the value of copy, then “I am suceed” is displayed, otherwise “I am lost”.
But as per the while loop opted in the code, the number is equivalent to the copy, therefore, “I am succeed” will be displayed as output.
Please find attached running output for this question for your reference.
