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I need help with these. Please try to show as much work possible! Thank you.
You have a protein solution of concentration 1 M. You need to make a series of six dilutions of 200 mM, 40 mM, 10 mM, 200 mu M, 40 mu M, and 10 mu M. Starting with the highest concentration, use the previously dilution to make the next dilution, and so on. You will need at least 6 mL of each concentration to conduct the experiment, so be sure to make extra. A harder one which requires a little more algebra. You have 500.0 mL of dH2O. How much glycerine would you have to add in order to make a 5.0% (v/v) dilution?
Expert Answer
7)
1M = 1000mM
Take 6 ml of 1000mM and dilute it to 200mM
We can calculate the volume of 200mM protein by using formula
V1N1=V2N2
6ml x 1000nM = V2 x 200mM
V2 = 6ml x 1000nM / 200mM = 30 ml
Now dilute 30 ml 200mM protein to 40mM
30 ml x 200mM = V3 x 40 mM
V3 = 30 ml x 200mM / 40 mM = 150 ml
Dilute 150 ml 40mM protein solution to 10 mM
150 ml x 40 mM = V4 x 10 mM
V4 = 150 ml x 40mM / 10 mM = 600 ml
Dilute 600 ml 10mM protein solution to 2000 µM
1mM = 1000 µM
10mM = 10000 µM
600 ml x 10000 mM = V5 x 200 µM
V5 = 600 ml x 10000 mM /200 µM = 30000 ml
Dilute 3000 ml 200 µM protein solution to 40 µM
3000 ml x 200 µM = V6 x 40 µM = 15000 ml
Dilute 15000 ml 40 µM protein solution to 10 µM
15000 ml x 40 µM = V7 x 10 µM
V7 = 15000ml x 40 µM /10 µM = 60000 ml
After 6 series of dilution volume of protein solution increased 10000 times.
6 ml 1M protein solution gives 6.0L (60000ml) of 10 µM protein solution
