You have a 12.0 gram sample of gold at 20.0°C. How much heat does it take to raise the temperature to 111.0°C?
Enter your answer in decimal form with three (3) sig figs. Use the proper abbreviation for the units.
Q = m * C * delta T
where, Q = heat
m = mass
C = specific heat capacity
delta T = (T2 – T1)
Q = 12.0 * 0.129 * (111.0 – 20.0)
Q = 12.0 * 0.129 * 91 = 140.8 J
Therefore, the heat required is 140.8 J