Question & Answer: What is the value of the equilibrium constant at 25 oC for the reaction between the pair…..

What is the value of the equilibrium constant at 25 oC for the reaction between the pair:

Mn(s) and Ag+(aq) to give Ag(s) and Mn2+(aq)

Use the reduction potential values for Ag+(aq) of +0.80 V and for Mn2+(aq) of -1.18 V

Give your answer using E-notation with NO decimal places.

*Should be 8E66

Expert Answer

Answer

2Ag+ + Mn(s) —-> 2Ag(s) + Mn+2

Eo = Eo cathode – Eo anode

Eo = Eo Ag+/Ag – Eo MN+2/Mn

Eo = 0.80 + 1.18

Eo = 1.98 V

we know that

dGo = – nFEo = -RT lnK

so

nFEo = RT ln K

here n = 2 as two electrons are transferred

2 x 96485 x 1.98 = 8.314 x 298 x ln K

K = 9.44 x 10^66

so equilibrium constant is 9.44 x 10^66

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