What is the molar solubility of Fe(OH)3 in a solution thatvis buffered at pH 2.50
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Answer
pH = 2.50
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pOH = 14-pH = 14-2.50 = 11.5
pOH = -log[OH–]
[OH–] = antilog(-pOH)
= antilog(-11.5)
[OH–] = 3.16*10-12M
Let the solubility be S moles/L
Fe(OH)3 <—> Fe3+ + 3OH–
Ksp = [Fe3+][OH–]3
6.3*10-38 = S*(3.16*10-12)3
S = 6.3*10-38 / 31.55*10-36
S = 1.99*10-3mol/L = 2.0*10-3mol/L
Option D