Question & Answer: What is the increase of the boiling point of a solution of 2.0 mol CaCl2 in 1 kg of water if the…..

What is the increase of the boiling point of a solution of 2.0 mol CaCl2 in 1 kg of water if the change is 0.51 c/mol of particles?

Expert Answer

Apply Colligative properties

We can favourincrease in BP via:

dTb = Kb*m*i

where i = total ions in solution, in this case CaCl2 = Ca+2 + 2Cl- = 1+2 = 3 ions

m = molalty = mol of solute / kg of solvent

1 kg of solvent, 2 mol

so

molality = 2/1 = 2

now;

dTb = 0.51*2*3 = 3.06 ºC

this is the increase in boiling point, i..e it will boil at 103.06 C

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