Question & Answer: What is the boiling point of a solution that contains 1.00 kg of water and each of the following…..

a) NaCl is ionic compound it dissociates to ions so i = 2

molality = moles / mass of solvent = 3.49 / 1 = 3.49 m

Tb = i x Kb x m

Tb = 2 x 0.512 x 3.49

Tb = 3.57

boiling point of solution = 100 + 3.57 = 103.57⁰C

b) as lactate is molecular compound i = 1

molality = 4.74 / 1 = 4.74

Tb = 0.512 x 4.74

Tb = 2.43

boiling point of solution = 100 + 2.43 = 102.43⁰C