The answer is not 10^15.5932 or 10^15.54 for some reason…
Use the appropriate standard reduction potentials in the appendix of your book to determine the equilibrium constant at 321.0 K for the following reaction under acidic conditions. See the hint for E degree values 4H^+ (aq) + MnO_2(s) + 2Fe^2+ (aq) rightarrow Mn^2+ (aq) +2Fe^3+ (aq) +2H_2O(l) K =
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