USA: +1 (725) 712-1730 
Sign in
The water-gas shift reaction plays an important role in the production of clean fuel from coal. CO(g) + H_2O(g) leftrightarrows CO_2(g) + H_2(g) Use the following thermodynamic data to determine the equilibrium constant K_p at 700. K.
Expert Answer
Enthalpy of reaction = sum of enthalpy of products- sum of enthalpy of reactants
For the reaction, deltaH= 1* deltaH of CO2+1* deltaH of H2- { 1* deltaH of CO+1*deltaH of H2O}
1,1,1 and 1 are coefficients of CO2, H2, CO and H2O respectively.
deltaH= 1*-393.5+1*0 –{ 1*-110.5+1*(-241.8)}=-41.2 KJ/mole
similarly, deltas= 213.7*1+1*130.7- ( 1*197.7+1*188.8)=-42.1 J.mol.K
deltaG= deltaH-T*delts = -41.2*1000+700*42.1 =-11730 J/mole
but deltaG=-RTlnK, K= equilibrium constant
-11730= -8.314*700*lnK
K= 7.5
