USA: +1 (725) 712-1730 
Sign in
The voltage generated by the zinc concentration cell described by, Zn(s)Zn^2+ (aq, 0.100)||Zn^2+ (aq M) Zn(s) is 26.0 mV at 25 degree C. Calculate the concentration of the Zn^2+(aq) ion at the cathode. Number M
Expert Answer
Answer
Number of electron being transferred in balanced reaction is 2
So, n = 2
Since this is concentration cell, Eo = 0.0. V
Use:
E = Eo – (0.0592/n) log {[Zn2+]^1/[Zn2+]^1}
0.026 = 0.0 – (0.0592/2) log (0.100/[Zn2+])
log (0.1/[Zn2+]) = -0.8784
(0.1/[Zn2+]) = 0.1323
[Zn2+] = 0.756 M
Answer: 0.756 M
