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The vibrational wavenumber of Br2 is 323.2 cm-1.
a) Evaluate the vibrational partition function
without approximation and plot its value as a function of temperature.
b) Determine the temperature at which the value obtained lies within 5% of the approximate value.
Expert Answer
Answer:
A) The vibrational partition function for diatomic particles is given by:
qvib =
= 323.2 cm-1
h – planks constant
k – stefen boltzman constant
-h/k =
= 465.16 K
Plot:
q vib = 1/(1-exp(465.16/T))
At room temp i.e 300 K
/T = 1.55
B) At room temperatue 300K qvib = 1.26. This implies, as before, that very few vibrational states are accessible.
temperature at which the value obtained lies within +5% of the approximate value is 300 K to 330K
