Question & Answer: The table to the right gives the concentrations of NO_2(g) as a function of time at a certain…..

The table to the right gives the concentrations of NO29, as a function of time at a certain temperature for the following reaction INO2] (M)time (s) 0.0831 0.0666 0.0567 0.0497 0.0 4.2 7.9 11.4 15.0 NO2(g) → NO(g) +-02(e) Determine the order of this reaction by graphing first and secord order plots using the data provided. 0.0441 Number Order of reaction Input the value of the rate constant below and select the correct units. Number

The table to the right gives the concentrations of NO_2(g) as a function of time at a certain temperature for the following reaction NO_2(g) rightarrow NO(g) + 1/2 O_2 (g) Determine the order of this reaction by graphing first and second order plots using the data provided. Order of reaction Input the value of the rate constant below and select the correct units. Number Ms^-1 s^-1 M^-1s^-1 M^-2s^-1

Expert Answer

Solution:

  • Step – 1:

Following is the Data (i.e.. given in the problem), as a Table, …obtained using MS Excel…in …image format…..

  • Step – 2:

Following is the plot of …… [NO2] (M) vs. Time (seconds)…obtained using above data & table and ..

MS excel….in…image format…..

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  • Step – 3:

Following is the plot… of ln[NO2] vs. Time (seconds)…obtained using above data & table and ..

MS excel….in…image format…..

  • Step – 4:

Following is the plot… of 1/[NO2] vs. Time (seconds)…obtained using above data & table and ..

MS excel….in…image format…..

  • Step – 5:

As we can see, from the above plots, only the …1/[NO2] vs. Time (seconds) …plot …is Linear….

therefore   We can surely say… that the Given Reaction is of …. Second Order…..

…..Order of the reaction RightarrowSecond Order  ….. (Answer <1>)…

  • Step – 6:

We know that the Rate Constant (i.e. ‘k’ ) would be = Slope … of the 1/[NO2] vs. Time (seconds)…. Plot… for this Second Order reaction.

therefore    k = (22.675 – 12.033) / (15.0 – 0.0 ) = 0.709

Therefore:

  • Rate Constant:    k = 0.709 M -1. s – 1  (i.e. for this Second Order reaction) ….. ( Answer <2> )
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