Question & Answer: The standard reduction potential for the reaction: 2 D^+(aq) + 2 e^? rightarrow D_2(g) where…..

The standard reduction potential for the reaction: 2 D+(aq) + 2 e → D2(g) where D is deuterium, is-0.0034V at 25°C. Calculate E° and K at 25°C for the reaction:

The standard reduction potential for the reaction: 2 D^+(aq) + 2 e^? rightarrow D_2(g) where D is deuterium, is ?0.0034V at 25 degree C. Calculate E degree and K at 25 degree C for the reaction: 2 H^+ (aq) + D_2(g) rightarrow 2 D^+(aq) + H_2(g)

Expert Answer

Reaction given:

2H+ + D2 —> 2D+ + H2

Here H+ is getting reduced and D2 is getting oxidized.

E0 = Eoxid + Ered = 0.0034 + 0 = 0.0034 V

Using relation:

E0 = (0.0591/n)*log K

Putting values we get:

0.0034 = (0.0591/2)*log K

Solving we get:

K = 100.115 = 1.303

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