Question & Answer: The external pressure on a gas sample is 2660 mmHg, and the volume changes from 0.88 L to…..

The external pressure on a gas sample is 2660 mmHg, and the volume changes from 0.88 L to 063 L at constant temperature. Find w (in kJ) done on the gas (1 atm middot L = 101.3 J).

Expert Answer

The work done $W = -PDelta V$

$W = -left ( dfrac { 2660 : mm : Hg}{ 760 : mm : Hg/atm} right ) times left ( 0.63 : L - 0.88 : L right )$

$W = 0.875 : L : atm$

Convert the unit from Latm to J.

$W = 0.875 : L : atm times 101.3 : J/L : atm$

$W = 88.6 : J$

Convert the unit from J to kJ

$W = 88.6 : J times dfrac {1 : kJ}{1000 : J}$

$W = 0.089 : kJ$

Still stressed from student homework?

Get quality assistance from academic writers!

Order now