Solid calcium carbonate decomposes to give solid calcium oxide and gaseous oxygen. Write the equilibrium constant for this reaction. Next, calculate the change in Gibbs energy associated with this reaction.
CaCO3(s) <—–> CaO(s) + CO2(g)
DG0rxn = DG0CO2+DG0CaO – DG0CaCO3
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Question & Answer: Solid calcium carbonate decomposes to give solid calcium oxide and gaseous oxygen…..
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= 131.4 kj
DG0 = – RTlnK
131.4*10^3 = -8.314*273.15lnk
k = equilibrium constant = 7.44*10^-26