Expert Answer
Answer
CaCO3(s) <—–> CaO(s) + CO2(g)
DG0rxn = DG0CO2+DG0CaO – DG0CaCO3
= (-603.3-394.4)-(-1129.1)
= 131.4 kj
DG0 = – RTlnK
131.4*10^3 = -8.314*273.15lnk
k = equilibrium constant = 7.44*10^-26
CaCO3(s) <—–> CaO(s) + CO2(g)
DG0rxn = DG0CO2+DG0CaO – DG0CaCO3
= (-603.3-394.4)-(-1129.1)
= 131.4 kj
DG0 = – RTlnK
131.4*10^3 = -8.314*273.15lnk
k = equilibrium constant = 7.44*10^-26