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Process Mean standa Deviation Lower Spec see
Determine if the following process are capable.
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Expert Answer
Process 1
USL = 7.02
LSL = 5.70
Cp = USL – LSL / 6*sigma = (7.02 – 5.70) / (6*0.15) = 1.467
Cpk = min[(USL – mean / 3*sigma), (mean – LSL / 3*sigma)] = min(7.02 – 6.25/3*0.15 , 6.25 – 5.70/3*0.15) = 1.22
All points in 6-sigma limits lie betwwen the USL, LSL range, hence the process is capable.
Process 2
USL = 8.60
LSL = 7.20
Cp = USL – LSL / 6*sigma = (8.60 – 7.20) / (6*0.18) = 1.297
Cpk = min[(USL – mean / 3*sigma), (mean – LSL / 3*sigma)] = min(8.60 – 7.90/3*0.18 , 7.90 – 7.20/3*0.18) = 1.296
All points in 6-sigma limits lie betwwen the USL, LSL range, hence the process is capable, also the process is perfectly centered.
