 # Question & Answer: Part A Complete the first row. Express your answer using two significant figures……

Part A

Complete the first row.

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Part B

Complete the first row.

[OH−] = 3.6•10.10 M

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Part C

Complete the first row.

pH = 8

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Part D

Complete the first row. Indicate whether the solution is acidic or basic.

Complete the first row. Indicate whether the solution is acidic or basic.

pOH = 5.7

Correct

Part E

Complete the second row.

 acidic basic

Part F

Complete the second row.

[H+] = M

Part G

Complete the second row.

pH =

Part H

Complete the second row. Indicate whether the solution is acidic or basic.

Complete the second row. Indicate whether the solution is acidic or basic.

pOH =

Part I

Complete the third row.

 acidic basic

Part J

Complete the third row.

[H+] = M

Part K

Complete the third row.

[OH−] = M

Part L

Complete the third row. Indicate whether the solution is acidic or basic.

Complete the third row. Indicate whether the solution is acidic or basic.

pOH =

Part M

Complete the fourth row.

 acidic basic

Part N

Complete the fourth row.

[H+] = M

Part O

Complete the fourth row.

[OH−] = M

Part P

Complete the fourth row. Indicate whether the solution is acidic or basic.

Complete the fourth row. Indicate whether the solution is acidic or basic.

pH =

Complete the following table by calculating the missing entries and indicating whether the solution is acidic or basic.

 [H+] [OH−] pH pOH Acidic or basic? 7.4×10−3M 3.6×10−10M 8.26 5.72

Given [H+] = 7.4*10^-3 M

As we know that

[H+] [OH-] = 10^-14

[OH-] = (10^-14)/[H+] = (10^-14)/(7.4*10^-3) = 1.35*10^-12 M

pH = – log[H+] = – log(7.4*10^-3) = 2.13 (acidic)

pH + pOH = 14

pOH = 14- pH = 14-2.13 = 11.87

Given [OH-] = 3.6*10^-10 M

As we know that

[H+] [OH-] = 10^-14

[H+] = (10^-14)/[OH-] = (10^-14)/(3.6*10^-10) = 2.77*10^-5 M

pH = – log[H+] = – log(2.77*10^-5) = 4.56 (acidic)

pH + pOH = 14

pOH = 14- pH = 14-4.56 = 9.44

Given pH = 8.26 (basic)

As we know that

pH = – log[H+]

8.26 = -log[H+]

[H+] = 10^(-8.26) = 5.5*10^-9 M

[H+] [OH-] = 10^-14

[OH-] = (10^-14)/[H+] = (10^-14)/(5.5*10^-9) = 1.82*10^-9 M

pH + pOH = 14

pOH = 14- pH = 14-8.26 = 5.74

Given pOH = 5.72

As we know that

pH + pOH = 14

pH = 14- pOH = 14-5.72 = 8.28 (basic)

pH = – log[H+]

8.28 = -log[H+]

[H+] = 10^(-8.28) = 5.25*10^-9 M

[H+] [OH-] = 10^-14

[OH-] = (10^-14)/[H+] = (10^-14)/(5.25*10^-9) = 1.90*10^-6 M