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Nitrosyl bromide decomposes according to the following equation. 2 NOBr(g) 2 NO(g) + Br_2(g) A 0.64 mol sample of NOBr was placed in a 1.00 L flask containing no NO or Br_2. At equilibrium, the flask contained 0.46 mol of NOBr. How many moles of NO and Br_2 are in the flask at equilibrium? A. 0.18 moles NO and 0.18 moles Br_2 B. 0.18 moles NO and 0.090 moles Br_2 C. 0.46 moles NO and 0.46 moles Br_2 D. 0.36 moles NO and 0.23 moles Br_2
Expert Answer
Answer
2NOBr(g) <—-> 2NO(g) + Br2(g)
initial 0.64 mol 0 0
change 0.18 mol 0.18 0.09
equil 0.46 mol 0.18 0.09
At equilibrium
No of mole of NO = 0.18
No of mole of Br2 = 0.09
answer: B
