Needed information for the problem
Conversion problem: The molecular weight of urea [CO (NH2)2] is 60. The molecular weight of blood urea nitrogen/serum urea nitrogen (BUN, N2) is 28.
Ratio and proportion problem: 60 g. mol. wt Urea/28 g. mol. wt BUN = mg/dL Urea/ mg/dL BUN
Convert a BUN of 15 mg/dL to mmoles/L. BUN __?__ mmol/L.
Show all work please, and report to the nearest tenth. Thanks.
The molecular mass of BUN is 28 g/mol.
We know that 1 dL = (1 dL)*(1 L/10 dL) = 0.1 L.
The concentration of BUN is 15 mg/dL = (15 mg/dL)*(1 g/1000 mg)*(1 mole/28 g)*(1000 mmol/1 mole) = 0.5357 mmol/dL = (0.5357 mmol)/(1 dL) = (0.5357 mmol)/(0.1 L) = 5.357 mmol/L ≈ 5.3 mmol/L (ans).