In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80 m/s2 . Ignore air resistance.A flea jumps straight up to a maximum height of 0.390 m . What is its initial velocity v0 as it leaves the ground?
Given acceleration due to gravity = a= 9.8m/s2
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Question & Answer: In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of…..
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distance (maximum height) = 0.390m
Final velocity= V1= 0
Inital velocity = V0= ?
Using the equation V12=V02+2* a* s
0= V02 + 2*(-9.8 m/s2) * (0.390 m)
V02 = 7.644 m2/s2
V0= 2.765 m/s
Hence the initial velocity is 2.765 m/s as it leaves the ground.