USA: +1 (725) 712-1730 
Sign in
In the coordination compound [Cr(NH3)(en)2Cl]Br2, the coordination number (C.N.) and oxidation number (O.N.) of the metal atom are…?
Can you please walk through step by step, I don’t understand how to find the coordination number at all!
Expert Answer
Answer
[Cr(NH3)(en)2Cl]Br2
outside 2 Br present means +2 charge present on complex
[Cr(NH3)(en)2Cl]+2
NH3 and en are neutral ligands so we take 0 for oxidation state calculation.
Cl is negetive ligand so we consider -1 in oxidation state calculation.
now assume X for Cr oxidation state.
X + 0 + 0 + (-1) = +2
X = +3
oxidation state of Cr = +3
NH3 is monodentate ligand
en is bidentate ligand
Cl also unidentate ligand
total 1 + 2 + 1 = 4
coordination number = 4
