Question & Answer: In a common car battery, six identical cells each carry out the following reaction: Pb + PbO2 +…..

In a common car battery, six identical cells each carry out the following reaction: Pb + PbO2 + 2HSO4 – + 2H+ → 2PbSO4 + 2H2O Suppose that to start a car on a cold morning, 138 amperes is drawn for 12.0 seconds from such a cell. How many grams of Pb are consumed? (The atomic mass of Pb is 207.19 g/mol.)

a. 0.562 g

b. 7.11 g

c. 1.78 g

d. 0.01235 g

e. 3.56 g

The answer is C, but I would like a detail soluntion.

Expert Answer

Answer

Pb + PbO2 + 2HSO4^– + 2H+ → 2PbSO4 + 2H2O

Pb^2+(aq) + 2e- ————–> Pb(s)

Z = 2

F = 96500c

C = 138amp

t = 12sec

W = MCt/ZF

= 207.19*138*12/2*96500

W = 1.78g

c. 1.78 g >>>>>>>>>>answer

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