Question & Answer: if item in c: c[item] = [c[item], b[item]] return c def mystery5(c): 1 = 0 for v in c.values()…..

Python

Refer to the following code: def mystery4(a, b): c = {} for item in a: c[item] = [a[item]] for item in b: if item in c: c[item] = [c[item], b[item]] return c def mystery5(c): 1 = 0 for v in c.values(): 1 + = len(v) return 1 d1 = {“a”: “alpha, “b”: “beta”, “d”: “delta”, “e”: “eta”, “z”:: d2 = {“a”: 1, “b”: 2, “c”: 3, “d”: 4, “e”: 5}