Question & Answer: Given the following acid dissociation constants, K_a (HF) = 7.2 times 10^-4 K_a…..

11. Given the following acid dissociation constants, Ka (HF) = 7.2 × 10-4 K, (NH4+) = 5.6 × 10-10 determine the equilibrium constant for the reaction below at 25 °C. HF(aq) + NH3(aq) → NH4+(aq) + F(aq) a. 4.0x 10-13 b. 1.3×10-8 c. 7.8 x 10-7 d. 1.3×106 e. 2.5×1012 What is the H30+ concentration in 0.45 M HCN(aq)? (Ka of HCN = 4.0 × 10-10) a. 4.0x 10-10 M b, 1.8×10-10 M c. 1.3×10-5M d. 2.0× 10.5M e. 0.45 M _. 12. 13. What is the pH of 0.015 M aqueous benzoic acid? (Ka of CsH&CO,H-6.3 x 10) a. 1.82 b. 3.03 C. 4.20 d. 6.02 e. 12.18

Given the following acid dissociation constants, K_a (HF) = 7.2 times 10^-4 K_a (NH^+_4) = 5.6 times 10^-10 determine the equilibrium constant for the reaction below at 25 degree C. HF(aq) + NH_3(aq) rightarrow NH^+_4 (aq) + F^-(aq) a. 4.0 times 10^-13 b. 1.3 times 10^-8 c. 7.8 times 10^-7 d. 1.3 times 10^6 e. 2.5 times 10^12 What is the H_3O^+ concentration in 0.45 M HCN(aq)? (K_a of HCN = 4.0 times 10^-10) a. 4.0 times 10^-10 M b. 1.8 times 10^-10 M c. 1.3 times 10^-5 M d. 2.0 times 10^-5 M e. 0.45 M What is the pH of 0.015 M aqueous benzoic acid? (K_a of C_5H_6CO_2H = 6.3 times 10^-5) a. 1.82 b. 3.03 c. 4.20 d. 6.02 e. 12.18

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Question & Answer: Given the following acid dissociation constants, K_a (HF) = 7.2 times 10^-4 K_a..... 1

Question & Answer: Given the following acid dissociation constants, K_a (HF) = 7.2 times 10^-4 K_a..... 2Question & Answer: Given the following acid dissociation constants, K_a (HF) = 7.2 times 10^-4 K_a..... 3Question & Answer: Given the following acid dissociation constants, K_a (HF) = 7.2 times 10^-4 K_a..... 4

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