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Question & Answer: For the combustion acetylene at 298.15 k…..

Question 21 (1 point) For the combustion of acetylene at 298.15 K, 2 C2H2(g) + 5。2(g) → 4 CO2(g) + 2 H2O(g) calculate AS (universe) given AS (system) -194.6 J/K and AlP(system) -2511.2 kJ. -2453.2 J/K -186.2 J/K +186.2 J/K +1290.4 J/K +8228.0 J/K Save

For the combustion acetylene at 298.15 k

Expert Answer

DeltaS°universe = DeltaS°system + DeltaS°surroundings

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DeltaS°system = -194.6J/K (given)

DeltaS°surroundings = -delta°H/T

delta°H = -2511.2kJ

T = 298.15K

DeltaS°surroundings = -(-2511.2kJ)/298.15K = 8.4226kJ/K = 8422.6 J/K

DeltaS°universe = -194.6J/K+8422.6J/K = 8228J/K (option E)

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