E. Jones Ltd, a light engineering company, wishes to know if they are maintaining the manufacturing average of 3% increase in productivity. The data in Table Old represents a month from last year and an equivalent month this year. Calculate the productivity change for each category using the costs provided, show the productivity change on a multifactor basis with euro as the common denominator.
Expert Answer
Last year | Now | Cost | |
Units produced | 1000 | 1000 | |
Labour (Hours) | 300 | 275 | 10/hr |
Materials (Kg) | 10,000 | 11,000 | 5/kg |
Energy (BTU) | 3000 | 2850 | 0.50/BTU |
1) Productivity change for each category –
Productivity = Output / Input
So, for each category, change in the productivity has to be calculated.You cannot add the categories together because they do not share the same units.
Last Year | Now | Change | |
Labour (hours) | 1000/300 = 3.33 | 1000/275 = 3.64 | 3.64 – 3.33 = 0.31 |
Material (000kg) | 1000/10000 = 0.1 | 1000/11000 = 0.09 | 0.09 – 0.1 = -0.01 |
Energy (BTU) | 1000/3000 = 0.33 | 1000/2850 = 0.35 | 0.35 – 0.33 = 0.02 |
Then for the improvement in the labour category:
0.31/3.33 = 0.093 or 9.3% improvement over last year.
2)
Last Year | Now | |
Labour (hours) | 300*10 = 3000 | 275*10 = 2750 |
Material (000Kg) | 10000*5 = 50000 | 11000*5 = 55000 |
Energy (BTU) | 3000*0.50 = 1500 | 2850*0.50 = 1425 |
Total Cost | 54,500 | 59,175 |
Multifactor productivity for last year = 1000/54500 = 0.018 units/
Multifactor productivity for current year = 1000/59175 = 0.016 units/
Change in productivity = 0.016/0.018 = 0.088 or 8.8%