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![7. (10 points) Consider the following function. (a) What would be the response to the call fun with no arguments? (b) Rewrite it (the function and default x) so that it evaluates post fix notation expres- sions that are formed as nested cell arrays. function [t]- fun (x) if nargin-= 0 x- 15 692518 6: end if iscel1(x) switch x(1) case + case - case t = fun (x(2)) + fun (x(3)); t fun (xf2)) fun (x(3)); t = fun(x(2)) * fun (x(3)); t = fun (x(2)) / fun (x(3)); case , end else t = x; end](https://media.cheggcdn.com/media%2Fbc8%2Fbc8f812d-5a64-4e9f-9f20-5da95ab4bfff%2Fimage "Question & Answer: Consider the following function. (a) What would be the response to the call fun with no arguments? (b) Rewrite it (the function an..... 1")
Consider the following function. (a) What would be the response to the call fun with no arguments? (b) Rewrite it (the function and default x) so that it evaluates post fix notation expressions that are formed as nested cell arrays. function [t] = fun(x) if nargin == 0 x = { ‘+’ { ‘-‘ { ‘*’ 9 2 } 5} { ‘/’ 18 6 } } }: end if iscell(x) switch x(1) case ‘+’ t = fun (x{2}) + fun (x{3}): case ‘-‘ t = fun (x{2}) – fun (x{3}): case ‘*’ t = fun(x{2}) * fun (x{3}): case ‘/’ t = fun (x{2})/fun (x{3}): end else t = x: end
Expert Answer
[a]
Code :
function [t] = fun(x)
if nargin ==0
x = {‘+’ {‘-‘ 15 6} {‘-‘ {‘-‘ {‘*’ 9 2} 5 } {‘/’ 18 6}}};
end
if iscell(x)
switch x{1}
case ‘+’
t= fun(x{2}) + fun(x{3});
case ‘-‘
t = fun(x{2}) – fun(x{3});
case ‘*’
t = fun(x{2}) * fun(x{3});
case ‘/’
t = fun(x{2}) / fun(x{3});
end
else
t =x;
end
Result :
