Question & Answer: Consider the following data: NH3(g)—> (1/2)N2(g)+(3/2)H2(g) DeltaH= 46 KJ…..

Consider the following data: NH3(g)—> (1/2)N2(g)+(3/2)H2(g) DeltaH= 46 KJ

2H2(g)+ O2(g)—–> 2H2O(g) DeltaH= -484KJ

Calculate ΔH for the reaction

2N2(g)+6H2O(g)—–>3 O2(g)+4NH3(g)

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