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![10 Final Exam 11. (10 points) Consider the following code. What is printed by ure function definitions? Pay attention to when fprintf functions are triggered to function q -enqueue(v, q) 9-tv end v)i fprintf (enqueing ld into queue In. function Iv q) - dequeue(q) q(end); fprintf(deque ing%d from queuen q = q(1:end-1); end function s - push(v. ) s- (v s]; fprintf ( , pushing %d onto stackla, v); end function [v s] = pop(s) vs(1); fprintfC popping ld from stackin, v) s = s(2:end); end s1 = [1]; s2 = [23]; q = [4 5]; (v s2) = pop(s2); q = enqueue(v, q) (v q] = dequeue (q); s2 = push(v, S2) (v s2] = pop(s2); s1 = push(v, sl) [v ql - dequeue (g); s1 = push(v, sl) (v q] = dequeue(q); 82 push(v, s2) (v s2] = pop(s2); s1 = push (v, sl) disp(s1); disp(s2); disp(q):](https://media.cheggcdn.com/media%2F6d6%2F6d6072b4-aafa-4863-b1c3-2aa0350f682f%2Fimage)
Consider the following code. What is printed by the code that follows the function definitions? Pay attention to when fprintf functions are triggered. function q = enqueue (v, q) q = [v q]: fprintf(‘enqueing %d into queuen’, v): end function [v q] = dequeue(q) v = q(end): fprintf(‘dequeing %d from queuen’, v): q = q(1: end-1): end function s = push(v, s) s = [v s]: fprintf(‘pushing %d onto stackn’, v): end function [v s] = pop(s) v = s(1): fprintf(‘popping %d from stackn, v): s = (2: end): end s1 = [1]: s2 = [2 3]: q = [4 5]: [v s2] = pop(s2) q = enqueue(v, q) [v q] = dequeue(q): s2 = push(v, s2): [v s2] = pop(s2): s1 = push(v, s1) [v q] = dequeue(q): s1 = push(v, s1) [v q] =dequeue(q): s2 = push(v, s2) [v s2] = pop(s2) [v s2] = pop(s2): s1 = push(v, s1) disp(s1): disp(s2): disp(q);
Expert Answer
Code;
function q = enqueue(v, q)
q = [v q]; fprintf(‘enqueing %d into queuen’, v);
end
function [v q] = dequeue(q)
v = q(end); fprintf(‘dequeing %d from queuen’, v);
q = q(1:end-1)’
end
function s = push(v, s)
s = [v s]; fprintf(‘pushing %d onto stackn’, v);
end
function [v s] = pop(s)
v = s(1); fprintf(‘popping %d from stackn’, v);
s = s(2:end);
end
s1 = [1];
s2 = [2 3];
q = [4 5];
%v = 2, s2 = [3]
[v s2] = pop(s2);
% q = [5 4 2]
q = enqueue(v, q);
% v=5, q = [4 2]
[v q] = dequeue(q);
% s2 = [5 3]
s2 = push(v, s2);
% v = 5, s2 = [3]
[v s2] = pop(s2);
% s1 = [5 1]
s1 = push(v, s1);
% v = 4, q = [2]
[v q] = dequeue(q);
% s1 = [4 5 1]
s1 = push(v, s1);
% v = 2, q = []
[v q] = dequeue(q);
% s2 = [2 3]
s2 = push(v, s2);
% v = 2, s2 = [3]
[v s2] = pop(s2);
% s1 = [2 4 5 1]
s1 = push(v, s1);
fprintf(“n”);
% 2 4 5 1
disp(s1);
% 3
disp(s2);
% []
disp(q);
