Consider the following code. What is printed by the code that follows the function definitions? Pay attention to when fprintf functions are triggered. function q = enqueue (v, q) q = [v q]: fprintf(‘enqueing %d into queuen’, v): end function [v q] = dequeue(q) v = q(end): fprintf(‘dequeing %d from queuen’, v): q = q(1: end-1): end function s = push(v, s) s = [v s]: fprintf(‘pushing %d onto stackn’, v): end function [v s] = pop(s) v = s(1): fprintf(‘popping %d from stackn, v): s = (2: end): end s1 = [1]: s2 = [2 3]: q = [4 5]: [v s2] = pop(s2) q = enqueue(v, q) [v q] = dequeue(q): s2 = push(v, s2): [v s2] = pop(s2): s1 = push(v, s1) [v q] = dequeue(q): s1 = push(v, s1) [v q] =dequeue(q): s2 = push(v, s2) [v s2] = pop(s2) [v s2] = pop(s2): s1 = push(v, s1) disp(s1): disp(s2): disp(q);

## Expert Answer

**Code;**

function q = enqueue(v, q)

q = [v q]; fprintf(‘enqueing %d into queuen’, v);

end

function [v q] = dequeue(q)

v = q(end); fprintf(‘dequeing %d from queuen’, v);

q = q(1:end-1)’

end

function s = push(v, s)

s = [v s]; fprintf(‘pushing %d onto stackn’, v);

end

function [v s] = pop(s)

v = s(1); fprintf(‘popping %d from stackn’, v);

s = s(2:end);

end

s1 = [1];

s2 = [2 3];

q = [4 5];

%v = 2, s2 = [3]

[v s2] = pop(s2);

% q = [5 4 2]

q = enqueue(v, q);

% v=5, q = [4 2]

[v q] = dequeue(q);

% s2 = [5 3]

s2 = push(v, s2);

% v = 5, s2 = [3]

[v s2] = pop(s2);

% s1 = [5 1]

s1 = push(v, s1);

% v = 4, q = [2]

[v q] = dequeue(q);

% s1 = [4 5 1]

s1 = push(v, s1);

% v = 2, q = []

[v q] = dequeue(q);

% s2 = [2 3]

s2 = push(v, s2);

% v = 2, s2 = [3]

[v s2] = pop(s2);

% s1 = [2 4 5 1]

s1 = push(v, s1);

fprintf(“n”);

% 2 4 5 1

disp(s1);

% 3

disp(s2);

% []

disp(q);