Question & Answer: Consider the following code. What is printed by the code that follows the function definitions? Pay attention…..

Code;

function q = enqueue(v, q)
q = [v q]; fprintf(‘enqueing %d into queuen’, v);
end

function [v q] = dequeue(q)
v = q(end); fprintf(‘dequeing %d from queuen’, v);
q = q(1:end-1)’
end

function s = push(v, s)
s = [v s]; fprintf(‘pushing %d onto stackn’, v);
end

function [v s] = pop(s)
v = s(1); fprintf(‘popping %d from stackn’, v);
s = s(2:end);
end

s1 = [1];
s2 = [2 3];
q = [4 5];

%v = 2, s2 = [3]
[v s2] = pop(s2);

% q = [5 4 2]
q = enqueue(v, q);

% v=5, q = [4 2]
[v q] = dequeue(q);

% s2 = [5 3]
s2 = push(v, s2);

% v = 5, s2 = [3]
[v s2] = pop(s2);

% s1 = [5 1]
s1 = push(v, s1);

% v = 4, q = [2]
[v q] = dequeue(q);

% s1 = [4 5 1]
s1 = push(v, s1);

% v = 2, q = []
[v q] = dequeue(q);

% s2 = [2 3]
s2 = push(v, s2);

% v = 2, s2 = [3]
[v s2] = pop(s2);

% s1 = [2 4 5 1]
s1 = push(v, s1);

fprintf(“n”);

% 2 4 5 1
disp(s1);
% 3
disp(s2);
% []
disp(q);