USA: +1 (725) 712-1730 
Sign in
Can anyone please help me with this problem and explain to me? Thank you!
A bowler’s scores for six games were 182, 161, 186, 190, 173, and 178. Using these data as a sample, compute the following descriptive statistics
a. Range:
b.Variance (to 1 decimals):
c. Standard deviation (to 2 decimals):
d. Coefficient of variation (to 2 decimals):
Expert Answer
Given sample data for 6 scores
Sample Mean (x-bar) = (182+161+186+190+173+178)/6 = 178.33
a) Range (R) = Max(scores) – Min(scores) = 190-161 = 29
b) Sample Variance (s2) = (xi-x-bar)2/n-1 = 107.5 (by substituting the corresponding values.
c) Standard Deviation(s) = SQRT(Sample Variance) = SQRT(s2) = 10.37
d) Coefficient of Variation (COV) = (s/x-bar)*100 = (10.37/178.33)*100 = 5.81C
