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Calculate the standard free-energy change at 25 degree C for the following reaction. Use standard electrode potentials. 3Cu_(s) + 2NO_3_(aq) + 8H_(aq)^+ rightarrow 3Cu_(aq)^2+ + 2NO_(g) + 4 H_2O_(l)
Expert Answer
For the given reaction,
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Question & Answer: Calculate the standard free-energy change at 25 degree C for the following reaction…..
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At Cathode Reduction takes place.
2 NO3- (aq) + 8 H+ ——> 2 NO(g) + 4 H2O (l)
In the above reaction for N atom Oxidation state changes from +5 to +2
At anode oxidation takes place,
3 Cu (s) ——-> 3 Cu+2 (aq)
In the above reaction for Cu atom oxidation changes from 0 to +2
E0 cell = E cathode – E anode
E0 cell = 1 – 0.34
E0 cell = 0.66
we know free energy change dG = -nFE0
n = number of electrons transferd in the given reaction
F = Faraday
dG = – 6 * 96500 * 0.66
dG = -382140 J
dG = -382.14 kJ
