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Balance the following reaction in KOH. What are the coefficients in front of H_2O and KOH in the balanced reaction and list which side of the equation that H_2O and KOH appear? C_10H_22O_2(aq) + KMnO_4(aq) rightarrow C_10H_16O_4K_2(aq) + MnO_2(aq) A) H_2O = 1, KOH = 4, left B) H_2O = 4, KOH = 1, left C) H_2O = 8, KOH = 2, right D) H_2O = 3, KOH = 2, right E) H_2O = 4, KOH = 2, left
Expert Answer
Option (B) is correct as after adding -:
H2O = 4 and KOH 1, left
equation will be balanced .
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