Question & Answer: An experiment you are performing in your lab requires you to generate bromine gas…..

2 H₂O + 2 e^– → H₂ + 2 OH^– E^o = -0.83 V
Br₂ + 2 e^– → 2 Br^– E^o = 1.09 V

*** The answer is not 117.5 A***

Expert Answer

Answer

Note that 1 mol of Br2 gas; requires 2 mol of e-

8.77 mol of Br2 will require = 8.77×2 = 17.54 mol of e-

now; for current:

I = C/t

C = charge requried

1 mol of e- = 96500 C

17.54 mol of e- = x C

x = 17.54*96500 = 1,692,610 C

time = 1 hour… 3600 s

I = C/t= (1,692,610/3600)

I = 470.1694 C/s at least

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