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A system expands from a volume of 100 L to 2.00L against e constant external pressure of 1, 00 arm. What is the work (w) done by the system? (1L atm = 101.3 J) 1.00J 2.00J 1.01 times 10^2 J 1.01 times 10^5 j 3.00J
Expert Answer
Work = force * distance for a chemical change
W = -p*∆V
where P is pressure in Pa
V is volume in m^3
so 1atm = 1.01*10^5 Pa and the change in volume is
2.0L – 1.0L = 1.0 L = 1.0*10^-3
The work is
W = -1.01*10^5 Pa * 1.0*10^-3 m^3
W = -101 j
W = 1.01*10^2 j
The negative sign indicates work done by the system and represents energy lost by the system
