# Question & Answer: A student runs the reaction below with 183 mL of 0.613 M sulfuric acid (H2SO4). If the…..

A student runs the reaction below with 183 mL of 0.613 M sulfuric acid (H2SO4). If the sodium hydroxide is 0.280 M, how many milliliters will be needed for the reaction?

H2SO4 + 2 NaOH → Na2SO4 + 2 H2O

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Question & Answer: A student runs the reaction below with 183 mL of 0.613 M sulfuric acid (H2SO4). If the…..
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Report your answer in milliliters (mL) with the correct number of significant figures

$V_{NaOH} = \dfrac { M_{H2SO4} \times V_{H2SO4}}{M_{NaOH}} \times \text { basicity of } H_2SO_4$
$V_{NaOH} = \dfrac { 0.613 \: M \times 183 \: mL}{ 0.280 \: M} \times 2$
$V_{NaOH} = 801 \: mL$