A reaction that is used in the production of sulphuric acid can be described by the chemical equation 2SO_2(g) + O_2(g) 2SO_3(g) If initially [SO_2]_0 = 8.500 M, [O_2]_0 = 3.500 M, and [SO_3]_0 = 5.575 M, and if [O_2] = 0.075 M at equilibrium, then calculate the equilibrium values of [SO_2] and [So_3].
Since the concentration of O2 is going to be lower at equilibrium, the equilibrium must shift to the right.
2SO2 + O2 <–> 2SO3
I 8.5M 3.5M 5.575M
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Question & Answer: A reaction that is used in the production of sulphuric acid can be described by the chemical…..
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C -2x -x +2x
E 8.5 -2x 3.5 – x 5.575 + 2x
Since the equilibrium of O2 is given, we can solve for x:
Plug this value into the equilibrium concentrations of So2 and So3:
[so2]= 8.5 – 2(3.425)
[S03]=5.575 + 2(3.425)