Question & Answer: A piece of aluminum at 81.9°C is placed in a calorimeter containing 75.0 grams of water at…..

A piece of aluminum at 81.9°C is placed in a calorimeter containing 75.0 grams of water at 24.9°C. If the temperature at equilibrium is 28.3°C, what is the mass of the aluminum?

Expert Answer

First, let us define the heat baalance:

Qgain = -Qlost

Qgain = water

Qlost = aluminium

now, get heat equations

Qwater = mwater*Cwater*(Tf-Twater)

Qmetal = mmetal * Cmetal ( Tf-Tmetal)

now; substitute

mwater*Cwater*(Tf-Twater) = – mmetal * Cmetal ( Tf-Tmetal)

substitute known data

75*4.184*(28.3-24.9) = -mmetal * 0.9 * (28.3-81.9)

solve for mmetal

1,066.92 = 48.24*mmetal

m metal = 1,066.92/ 48.24

m metal = 22.1169 g of aluminium was used

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