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A) HBr B) BH_3 C) NaOH D) H_2O, H_2SO_4 heta E) H_3O^+ (workup) F) Hg(OAc)_2, CH_3OH G) NaBH_4, NaOH, H_2O H) mCPBA I) Br_2, CCl_4 J) Br_2, H_2O K) Br_2, CH_3CH_2OH L) OsO_4, H_2O_2 M) CH_3CH_2OH, H_2SO_4 N) CH_3CH_2ONa, CH_3CH_2OH O) (CH_3)_3CONa, (CH_3)_3COH P) H_2O_2, NaOH, H_2O Q) H_2, Pd/C R) ROOR S) CF_3COOH T) LiAIH_4 U) CH_3OH, H_2SO_4 V) CH_3OH, CH_3ONa Look at the given synthesis and the provided reagents. Fill in the blanks with the single letter code of the appropriate reagent, or the appropriate descriptive vocabulary word/phrase to complete the description. Remember the computer is very literal so check your spelling carefully. First addition of reagent forms the (functional group) Then reagents and together to give the (functional group) with regioselectivity. Then reagent to give the (functional group) with regioselectivity and lastly reagent to give the final diol product with stereoselectivity. The final product will be (single isomer/mixed stereoisomers) and the isomer ratio (will/will not) be influenced by the stereochemistry of the methyl group.
Expert Answer
Organic chemistry
First addition of reagent C forms the alkene. Then reagents B and P together to give the alcohol with syn regioselectivity. Then reagent D to give the alkene with cis regioselectivity and lastly reagent L to give the final diol with syn stereoselectivity. the fnal product will be mixed stereoisimers and the isomer ratio will be influenced by the stereochemistry of the methyl group.
