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A certain substance has a heat of vaporization of 33.79 kj/mol. At what Kelvin temperature will the vapor pressure be 3.00 times higher than it was at 351 K? K
Expert Answer
Answer
Clausius clapeypeon equation
ln( P1 / P2) = ∆H / R .( 1/T2 -1/T1)
The pressure measured at this new temperature will be 3 times bigger than P1.so we can write P2 = 3.P1
ln( P1 / 3.P1) = 33790/8.31446 ( 1/T2 – 1/351 K)
ln(1/3) = 4064 .1/T2 – 4064.1/351
-1.099 = 4064/T2 – 11.6
10.5 = 4064 / T2
T2 = 4064 / 10.5
T2 = 387 k
