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A 40.0 wt% solution of CsCl (mw = 168.37) has a density of 1.43 g/mL. Find the molarity of CsCl in the solution. Find the molality of CsCl in the solution
Expert Answer
Answer
Molarity = (mass % x 10 x density/ MW)
Molarity = (40 x 10 x 1.43 / 168.37)
Molarity = 572 / 168.37
Molarity = 3.40 M
