Question & Answer: 20.0 g of water at 75°C is added to a mixture of 50.0 g ice and 50.0 g water at 0°C in an…..

Step I

Heat of fusion of ice = 334.166 J g^-1

Heat gained by ice = 334.166 x 50 = 16708.3 J

Step II

Heat released by water at 75^oC = 20 x 4.184 x 75 = 6276 J

Step III

Mass of ice will not be melted completely.

Q = m (delta H fusion)

6276 = m x 334.166

m = 18.78 g

Step IV

Hence, the amount of ice remained = 50 – 18 = 32 g