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16. What is the molarity of the solution prepared by diluting 35.0 mL of 1.25 M AgNO3 to each of the following final volumes?. Show math expressions with substitutions. (a) 748 mL (b) 2.36 L M 17. What is the molarity of the solution prepared by concentrating, by evaporation of solvent, 750.0 mL of 0.200%(m/v) NaNO3 to a volume of 550.0 mL Show math. 4
Expert Answer
Q16.
M = mol / Volume, by definition
Apply Dilution law:
M1*V1 = M2*V2
so…
M2 = M1*V1/V2 always true
M2 = (35 mL *1.25 M)/(748 mL)
M2 = 0.05848 M
b)
for V = 2.36 L, change to mL = 2360 mL
substitute
M2 = M1*V1/V2 always true
M2 = (35 mL*1.25 M)/(2360 mL)
M2 = 0.018538 M
Question 17.
Once again, we can use dilution law
now we use mass by volume concentrations
C1*V1 = C2*V2
where C is the ocncentration by mass and volume of the sample
this is concentrating, so expect C2 > C1
Solve for C2
C2 = C1*V1/V2
C2 = 0.2% * 750 mL/ 550 mL
C2 = 0.2727 %
