125 mL of HCl was found. Without knowing the concentration you add 0.1 M NaOH until the equivalence point was reached. In total you added 225 mL of NaOH. What is the pH at equivalence point and what is the concentration of HCl?
Expert Answer
Answer
moles of NaOH added= molarity* Volume in Liter=0.1*225/1000= 0.0225
The reaction betwen HCl and NaOH is HCl+ NaOH—->NaCl + H2O
1 mole of HCl requires 1 mole of NaOH
moles of HCl at equivalence point= 0.0225
Volume of HCl used= 125ml= 125/1000L=0.125L
Concentration of HCl =0.0225/0.125 =0.18M
since both HCl and NaOH are strong acid and bases, at equivalence point pH=7.