 # Answered! Project 2 Let consider the intervals I1 = [-π, π], I2 = [5, 99], and I3 = ]-50, -4[. ( [, ] for inclusive and ], [ for excusive)…

Project 2

Let consider the intervals I1 = [-π, π], I2 = [5, 99], and I3 = ]-50, -4[.
( [, ] for inclusive and ], [ for excusive)
Write a C++ script to perform the following:
1) Define PI (π) as a constant and set it value rounded to 4 decimal places.
2) Ask the user to enter a real number
3) Save the user response as a variable a of type float
4) If a belongs to the interval I1 = [-π, π] , display on the console “a is between – PI and
PI” and “a is not between –PI and PI” otherwise.
5) If a belongs to the interval I2 = [5, 99]   , display on the console “a is between 5 and 99”
and “a is not between 5 and 99” otherwise.
6) Ask the user to enter a the value of an angle in degrees, you save the entry as
angleInDegrees. Compute its value in radians into the variable angleInRadians; print out:
7) Ask the user to enter the coordinates of two points A = (x1, y1) and B = (x2, y2)
8) Save the variables x1, y1, x2, and y2 as type float
9) Display on the console the coordinates of the mid-point M = ((x1 + x2)/2, (y1 + y2)/2)
between A and B
10) Display on the console the distance between A and B using the relation:
distance = sqrt((x2 – x1)2 + (y2 – y1)2)

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Answered! Project 2 Let consider the intervals I1 = [-π, π], I2 = [5, 99], and I3 = ]-50, -4[. ( [, ] for inclusive and ], [ for excusive)…
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#include <iostream>

#include <math.h>
using namespace std;
#define PI 3.1416

int main() {
float a;
int degree;
float x1,y1,x2,y2;
cout<<“Enter a Real number :”<<endl;
cin>>a;
if(a>=PI && a<PI)
cout<<“a is between -pi and pi”<<“n”;
else
cout<<“a is not between -pi and pi”<<“n”;

if(a>=5 && a<99)
cout<<“a is between 5 and 99″<<“n”;
else
cout<<“a is not between 5 and 99″<<“n”;
cout<<“Enter a angle in degree: “<<“n”;
cin>>degree;
if(degree>=0 && degree<360)
{
/*radians = ( degrees * pi ) / 180 */
}
else{
cout<<“Invalid degree.”<<“n”;
}

cout<<“Enter the A(x1,y1):”<<“n”;
cin>>x1>>y1;
cout<<“Enter the B(x2,y2):”<<“n”;
cin>>x2>>y2;

cout<<“Mid Point of A,B: “<<(x1 + x2)/2<<(y1 + y2)/2<<“n”;

cout<<“Distance between A and B: “<<sqrt(((x2 – x1)/2) + ((y2 – y1)/2))<<“n”;
return 0;
}

Output:

Enter a Real number : 45
a is not between -pi and pi
a is between 5 and 99
Enter a angle in degree :45
Angle in Randians:0.7854
Enter the A(x1,y1) : 2 10
Enter the B(x2,y2) : 40 60
Mid Point of A,B: 21 35
Distance between A and B: 6.63325