Answered! Let consider the intervals I1 = [-π, π], I2 = [5, 99], and I3 = ]-50, -4[. ( [, ] for inclusive and ], [ for excusive)…

Let consider the intervals I1 = [-π, π], I2 = [5, 99], and I3 = ]-50, -4[.
( [, ] for inclusive and ], [ for excusive)
Write a C++ script to perform the following:
1) Define PI (π) as a constant and set it value rounded to 4 decimal places.
2) Ask the user to enter a real number
3) Save the user response as a variable a of type float
4) If a belongs to the interval I1 = [-π, π] , display on the console “a is between – PI and PI” and “a is not between –PI and PI” otherwise.
5) If a belongs to the interval I2 = [5, 99] , display on the console “a is between 5 and 99” and “a is not between 5 and 99” otherwise.
6) Ask the user to enter a the value of an angle in degrees, you save the entry as angleInDegrees. Compute its value in radians into the variable angleInRadians; print out: The angle you enter in degree is equivalent to angleInRadians radians.
7) Ask the user to enter the coordinates of two points A = (x1, y1) and B = (x2, y2)
8) Save the variables x1, y1, x2, and y2 as type float
9) Display on the console the coordinates of the mid-point M = ((x1 + x2)/2, (y1 + y2)/2) between A and B
10) Display on the console the distance between A and B using the relation:
distance = sqrt((x2 – x1)2 + (y2 – y1)2)

#include <iostream>

#include <cmath>
#include<iomanip>
#define PI 3.1416 //step 1
using namespace std;
int main()
{
cout << “Enter a real number” <<endl; //step 2
cin >> a; //step 3

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Answered! Let consider the intervals I1 = [-π, π], I2 = [5, 99], and I3 = ]-50, -4[. ( [, ] for inclusive and ], [ for excusive)…
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//step 4
if(a>-PI && a<PI){
cout << “a is between – PI and PI” <<endl;
}else{
cout << “a is not between -PI and PI” <<endl;
}

//step 5
if(a>5 && a<99){
cout << “a is between 5 and 99” <<endl;
}else{
cout << “a is not between 5 and 99” <<endl;
}

//step 6
cout << “Enter a the value of an angle in degrees” <<endl;
cin >> angleInDegrees;
cout << “The angle you enter in degree is equivalent to ” <<angleInRadians <<” radians” <<endl;

//step 7
cout << “Enter the coordinates of two points A = (x1, y1) and B = (x2, y2)” <<endl;
//step 8
cin >> x1;
cin >> y1;
cin >> x2;
cin >> y2;
//step 9
cout << “Coordinates of the mid-point M = (” <<(x1+x2)/2<<“,”<<(y1+y2)/2<<“) between A and B”<<endl;
//step 10
cout << “Distance between A and B = ” << sqrt(pow(x2 – x1,2) + pow(y2 – y1,2))<<endl;
}

OUTPUT:-