Answered! Hi Folks, I am really getting confused here, I dont know how to solve these problems based on the deseasonalized…

Hi Folks, I am really getting confused here, I dont know how to solve these problems based on the deseasonalized demands (yd) (i.e., without seasonal effect) by using simple linear regression formula to derive the sales forecast: Y = a + b X . Please help me to find the slope value (b) and Y- intercept value (a) and the forcast for quater 15, i.e., the III quater of year 4, and the forcast for quater 20 of the above problem . I would really apprecite it. Please please show me the work and how you came to the answers? I dont need directly answers without showing me the calcualtions and the method how you got to those answers please. I want to learn and understand the materials.The following table shows a firms sales for a product line during the 12 quarters of the past three years. x represents the quarter number and y represents the sales. The related data for the computation of linear regression model is also given (1) (2) (3) (4) 600 600 1,550 3.100 1.500 4,500 6,000 1,500 16 2,400 12,000 25 18,600 3,100 36 2,600 18,200 49 23,200 2900 64 34,200 3,800 81 4,500 100 10 45,000 121 4,000 44,000 144 12 4900 58,800 78 268,200 6500 33.350 By using the simple linear regression formula to derive the sales forecast: Y a bXAnswered! Hi Folks, I am really getting confused here, I dont know how to solve these problems based on the deseasonalized... 1Answered! Hi Folks, I am really getting confused here, I dont know how to solve these problems based on the deseasonalized... 2

Expert Answer

 In a Linear Regression Equation , where:

Y = a + b.x

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( Sum of all y values)x (Sum of all x^2 values) – (sum of all x values)x(sum of all xy values)

A = ——————————————————————————————————————-

n x ( Sum of all x^2 values) – ( sum of x values)^2

n x (sum of all values which are product of x.y) – ( sum of x values)x(sum of y values)

B = ———————————————————————————————————————-

n x ( Sum of all x^2 values) – ( sum of x values)^2

Here,

A = Y intercept value

B = Slope Value

N = number of data = 12

Sum of x values = 78

Sum of y values ( deseasonalized demand) = 33350.1

Sum of all values which are product of x.y = 265706.9

Sum of all x^2 values = 650

Therefore ,

33350.1 x 650 – 78 x 265706.9          21677565 – 20725138.2                952426.8

A=          —————————————   =      ——————————     =      ————– =   555.02

12 x 650 – 78×78                                   7800 – 6084                                   1716

12 X 265706.9 – 78 X 33350.1     3188482.8   – 2601307.8           587175

B =          ———————————–   =         —————————   =    ————-   =      342.17

12 X 650 – 78 X 78                             7800 – 6084                             1716

( OR 342.2 ROUNDED TO ONE DECIMAL POINT)

Therefore Linear regression Equation is :

Y =   555.02 + 342.17.X

Y = Forecast value for sales

X = Quarter number

Thus in order to find out sales value for quarter 16, we need to find out value of Y for X = 15

Accordingly,

Y = 555.02 + 342.17 x 15 = 555.02 + 5132.55 = 5687.57 ( 5688 rounded to nearest whole number)

Note : Value of Y 555.02 is nearest to value 554.9 ( which is one of the options in answer to question 7). Therefore answer to question 7 will be “554.9”

Similarly Forecast for quarter 20 will be:

Y = 555.02 + 342.17 X 20 = 555.02 + 6843.4 = 7398.42

Therefore answer as follows:

NEW SLOPE VALUE B FOR ABOVE PROBLEM = 342.2
Y INTERCEPT VALUE A FOR THE ABOVE PROBLEM = 554.9
FORECAST FOR QUARTER 15 FOR THE ABOVE PROBLEM = 5688
FORECAST FOR QUARTER 20 FOR THE ABOVE PROBLEM = 7398.42

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